Sorry if this question is really straightforward or has already been answered.
I hold an off peak return for a journey from London St Pancras to Derby for a weekday next week, stating travel via "any permitted route". The fastest train to complete this journey would obviously be a direct EMR intercity service to Derby.
However, if possible, I would like to stop off in Kettering to grab coffee with a friend and drop off some Christmas presents. This would involve getting a Nottingham bound EMR intercity service to Kettering, breaking my journey (which I understand my ticket permits), getting on another Nottingham bound service and then changing at Leicester for the Sheffield bound service calling at Derby.
I can't figure out if getting this slower train is permitted. Obviously you can break your journey at a station that your train would call at, but I can't figure out if you can take a different service on the same travel corridor to break your journey at an alternative station.
Again, it is likely this question has already been answered I'm just unsure how to word my search if that makes sense.
I hold an off peak return for a journey from London St Pancras to Derby for a weekday next week, stating travel via "any permitted route". The fastest train to complete this journey would obviously be a direct EMR intercity service to Derby.
However, if possible, I would like to stop off in Kettering to grab coffee with a friend and drop off some Christmas presents. This would involve getting a Nottingham bound EMR intercity service to Kettering, breaking my journey (which I understand my ticket permits), getting on another Nottingham bound service and then changing at Leicester for the Sheffield bound service calling at Derby.
I can't figure out if getting this slower train is permitted. Obviously you can break your journey at a station that your train would call at, but I can't figure out if you can take a different service on the same travel corridor to break your journey at an alternative station.
Again, it is likely this question has already been answered I'm just unsure how to word my search if that makes sense.

